# Using Equations To Solve Word Problems

This involve Adding to a Solution, Removing from a Solution, Replacing a Solution,or Mixing Items of Different Values Motion Word Problems are word problems that uses the distance, rate and time formula.

You may be asked to find the Value of a Particular Term or the Pattern of a Sequence Proportion Problems involve proportional and inversely proportional relationships of various quantities.

Having difficulty turning a word problem into an algebra equation? With this tutorial, you'll learn how to break down word problems and translate them into mathematical equations.

Knowing the mathematical meaning of words allows you to decipher word problems and gives you the power to write your own word problems, too!

Then, we need to solve the equation(s) to find the solution(s) to the word problems.

Translating words to equations How to recognize some common types of algebra word problems and how to solve them step by step: Age Problems usually compare the ages of people.Ratio Problems require you to relate quantities of different items in certain known ratios, or work out the ratios given certain quantities.This could be Two-Term Ratios or Three-Term Ratios Symbol Problems Variation Word Problems may consist of Direct Variation Problems, Inverse Variation Problems or Joint Variation Problems Work Problems involve different people doing work together at different rates.Take a look at these words and learn their mathematical translations.Setting up and solving an equation from a word problem can be tricky, but this tutorial can help.Break the problem down into smaller bits and solve each bit at a time.First, we need to translate the word problem into equation(s) with variables.The equations are generally stated in words and it is for this reason we refer to these problems as word problems. If the two parts are in the ratio 5 : 3, find the number and the two parts. With the help of equations in one variable, we have already practiced equations to solve some real life problems. Solution: Let one part of the number be x Then the other part of the number = x 10The ratio of the two numbers is 5 : 3Therefore, (x 10)/x = 5/3⇒ 3(x 10) = 5x ⇒ 3x 30 = 5x⇒ 30 = 5x - 3x⇒ 30 = 2x ⇒ x = 30/2 ⇒ x = 15Therefore, x 10 = 15 10 = 25Therefore, the number = 25 15 = 40 The two parts are 15 and 25. Then Robert’s father’s age = 4x After 5 years, Robert’s age = x 5Father’s age = 4x 5According to the question, 4x 5 = 3(x 5) ⇒ 4x 5 = 3x 15 ⇒ 4x - 3x = 15 - 5 ⇒ x = 10⇒ 4x = 4 × 10 = 40 Robert’s present age is 10 years and that of his father’s age = 40 years. Lever Problems deal with the lever principle described in word problems.Lever problem may involve 2 Objects or More than 2 Objects Mixture Problems involve items or quantities of different values that are mixed together.